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How can I tell which item assoicated with a TimePicker in a ListView has been modified?

GerryHGerryH USMember ✭✭✭
in Xamarin.Forms

I have a ListView that includes a TimePicker:

<ListView.ItemTemplate>
                  <DataTemplate>
                     <ViewCell>
                        <StackLayout Orientation="Horizontal">
                           <TimePicker Time="{Binding MyTimeSpan}" PropertyChanged="OnTimePickerPropertyChanged" >
                              <TimePicker.Format>hh:mm tt</TimePicker.Format>
                           </TimePicker>
                           <Label Text="{Binding Text}">
                              <Label.GestureRecognizers>
                                 <TapGestureRecognizer Tapped="ItemTextTapped" CommandParameter="{Binding Id}"></TapGestureRecognizer>
                              </Label.GestureRecognizers>
                           </Label>
                        </StackLayout>
                     </ViewCell>
                  </DataTemplate>
               </ListView.ItemTemplate>
            </ListView>

Then the event handler:

      void OnTimePickerPropertyChanged(object sender, PropertyChangedEventArgs args)
      {
         if (!args.PropertyName.Equals("Time"))
            return;
         TimePicker picker = (TimePicker)sender;
         // which Item is it?
      }

How can I tell which Item is associated with the TimePicker?

FYI, Firefox does not work with your website.

Tagged:

Best Answer

  • LandLuLandLu Xamurai
    Accepted Answer

    @GerryH Get the index using the code below:

    void OnTimePickerPropertyChanged(object sender, PropertyChangedEventArgs args)
{
    if (!args.PropertyName.Equals("Time"))
        return;
    TimePicker picker = (TimePicker)sender;
    // which Item is it?
    var singleModel = picker.BindingContext as YourModel;
    var index = ItemsSoruce.IndexOf(singleModel);
}

    ItemsSoruce here is your list view's ObservableCollection items source.

Answers

  • ClintStLaurentClintStLaurent USUniversity ✭✭✭✭✭

    @GerryH said:
    FYI, Firefox does not work with your website.

    Disable your ad-block plug-in. Same thing happened to me.

    How can I tell which Item is associated with the TimePicker?

    Huh? What you trying to accomplish by getting the UI element itself? That raises red flags.
    You already have the time that was chosen by the user because you're binding to it.
    And for some weird reason you're also raising a CLR event when the property is changed: That's going to include the sender which is the picker.
    And now you also want to get the UI picker element when you tap on a label?

    That reads a lot like you're struggling to find a way to accomplish something, because that's a metric ton of redundancy and logic incorrectly being handled at the UI layer.

    So what is it you're really trying to acoomplish and we can try to get you working along a better path.

  • GerryHGerryH USMember ✭✭✭

    I am using an ObservableCollection. It has multiple items in it. The user changes the time for one of the items in the collection, but I have no way of know which one.

  • ClintStLaurentClintStLaurent USUniversity ✭✭✭✭✭

    What? What do you mean "I don't know which one"? Huh?

    The user taps the Picker in the ListView. The time value is binded to the property on that item - on the model itself.
    The model that gets the change knows the change has happened. And since its all binded your UI updates automatically.

    Are you trying to micro-manage or react to a change on element of the collection - from some outside class?

    AGAIN I'm asking: What is the goal? What is it you're trying to achieve? Not how are you trying to achieve it - because what you're doing is weird... So not the how but the why. Why are you trying to track which element of the collection got a new time?

  • GerryHGerryH USMember ✭✭✭
    edited May 2019

    Goal - I'd like to update the sqlite database when the user updates the time field. But I don't which record to update.

  • LandLuLandLu Member, Xamarin Team Xamurai
    Accepted Answer

    @GerryH Get the index using the code below:

    void OnTimePickerPropertyChanged(object sender, PropertyChangedEventArgs args)
{
    if (!args.PropertyName.Equals("Time"))
        return;
    TimePicker picker = (TimePicker)sender;
    // which Item is it?
    var singleModel = picker.BindingContext as YourModel;
    var index = ItemsSoruce.IndexOf(singleModel);
}

    ItemsSoruce here is your list view's ObservableCollection items source.

  • ClintStLaurentClintStLaurent USUniversity ✭✭✭✭✭

    @GerryH said:
    Goal - I'd like to update the sqlite database when the user updates the time field. But I don't which record to update.

    When you got the record you got the ID from the database, right? So when you update the record, you use that same ID. You shouldn't need the index from the ListView. PIcture it this way... In the future you may want to let the user sort or filter the list you got from the database: Fetch once, then sort or filter. That would make the index an invalid way to track it back to the database. But its ID will always be its ID.

  • GerryHGerryH USMember ✭✭✭

    LandLu, my model load from sqlite, and it includes the Id (index). Thanks!

       public class MyModel : ObservableProperty
   {
      [PrimaryKey, AutoIncrement]
      public int Id { get; set; }
      // etc.
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